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Use the formula M1V1 = M2 V2

25 M X V1 = [4.1 x 10 -2 ]M x 1.5 L

V1 = [4.1 x10-2 x 1.5] / 25

V1 = 0.00246 L = 2.5 mL

Take 2.5 mL of 25 M HCl and put it in a analytical measuring flask and complete the rest volume with distilled water (until the total volume is 1500 mL).

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Q: What volume of 25 M HCl must be diluted to prepare 1.5 L of 4.1x10-2 M HCl?
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