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Q: What volume of 3.69 m ironiii nitrate is required to make 500 ml of 1.53 m ironiii nitrate solution?
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What volume of a 0.20 M silver nitrate solution is required to precipitate all the Cl - ion in the solution as AgCl?

You cannot make a solution of AgCl, it is an insoluble salt


What volume of a 0.20 M silver nitrate solution is required to precipitate all the Cl− ion in the solution as AgCl?

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How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?

By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.


What volume mL of a 4.54 M lead nitrate solution must be diluted to 894 mL to make a 1.28 M solution of lead nitrate?

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What is amount of caustic required to adjust pH of solution?

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Is potassium nitrate more dense than water?

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Prepare a working solution from a stock solution?

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How much water is needed to make a 0.150 m lead nitrate solution using 13.6 grams of lead nitrate?

Look up molecular mass of lead nitrate in the periodic table. Formula of lead nitrate is Pb(NO3)2 Molecular mass is 331.2 gm/mole A one molar solution has 1 mole per liter of solution. 13.6 grams/331.2 gm/mole = 0.041 moles 0.041 moles/0.15 molar = .274 liters This is not exactly correct, because when you add a solute to a solvent, the volume of the solution may be more or less than the original volume of solvent, depending upon the interaction of the solvent and the solute. Actually, the final volume of solution should be 0.274 liters. The most accurate way is to dissolve the solute is slightly less than the calculated amount of solvent needed, and then adjust the volume to the final amount after the solute is completely dissolved.


What volume of a 2.5M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50M acetic acid solution?

The answer is 20,15 mL.


What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare?

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What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?

400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.