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100 mL 5.0 M HCl solution (0.50 mol HCl) is sufficient to fully react with 3.00g Mg, which is 3 (g) / 12 (g/mol) = 0.25 mol Mg because it needs a molar '1 to 2' ratio with HCl:

(1) Mg + 2 HCl --> Mg2+ + H2 + 2 Cl-

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Q: What volume of 5.0 molar hydrochloric acid is needed to react with 3.00g of magnesium metal?
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