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The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
The molarity is o,2.
This depends on the desired pH, volume of solution, initial pH, etc.
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
25/1.05 = 23.81 ml (rounded)
You cannot make a solution of AgCl, it is an insoluble salt
You cannot make a solution of AgCl, it is an insoluble salt
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
add barium chloride or barium nitrate to a solution containing sulphate ions SO4 2-. To the same solution add hydrochloric acid in excess. OBSERVATIONS, a white precipitate which is insoluble in excess acid confirms presence of SO42- IF IT DISSOLVES then it confirms SO32- ----------------------------------------- 1) Add barium nitrate solution under acidic conditions (use an equal volume of hydrochloric acid) to the unknown solution 2) A white precipitate of barium sulphate forms if sulphate ions are present
The molarity is o,2.
43.28 M
This depends on the desired pH, volume of solution, initial pH, etc.
If the amount of solute in unit volume of the solution is high, it is called a concentrated solution If the amount of solute in unit volume of the solution is low, it is called dilute solution
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
Per USP, drug products containing a 100mL or less (single or multiple doses) either in solution or in solution constituted from sterile solids.
The answer is 20,15 mL.
2.92%1g=1mL so;2.19/75 = 0.02920.0292*100%= 2.92% NaCl in a solution with total volume of 75 mL