VKOH = 23 mL * 0.22 M / 0.12 M = 42.2 = 42 mL
in practice ,i found that :aluminum powder(pure metal)+potasa (solution)..=potasium aluminate+high amount of heat liberated +wet hydrogen (mixed with water vapor) PROJECT STUDY : How to manipulate this equation to make use of the products gained ? 1-) Hydrogen (drying plant) 2-)potasium aluminate (uses in several branches in industry ) 3-)precise control of the heat liberated (measuring the amount of heat) 4-) a very smart and precise control system of the entire plant (elements of control system i.e solenoid valves..selection of the construction metal of the chemical reactor..safety relief valves..reaction time..automation of system which deals with the residual...microprocessing control of the system 5-)How to make use of the enthalpy liberated to generate electricity ? PLEASE : THIS IS CONFIDENTIAL AND I NEED HELP FROM PROFESSORS TO WORK AS ONE GROUP.. Faithfully yours Ashraf soliman Chief Mechanical Engineer The Egyptian Radio and TV Union (ERTU).,in cairo Tel.(home);202 37769630 mobile; 202 012 524 14 54 Home address:35 el sahab street_nasr eldeen_el haram _ AL JIZAH province-EGYPT
Without stating units, it is impossible to answer this question accurately. However, the equation you would need is q=mc∆T, where q is the heat flow (the 53.0 listed, likely Joules), m is the mass of the unknown metal (11.1, likely grams), c is the specific heat of the metal (the unknown you need to solve for), and ∆T is the change in temperature of the metal (24.1-13.0, likely Celcius). Rearranged to solve for specific heat, the question is c=q/m∆T.
012 is typically rounded to 12. The 0 is not needed in front of a whole number.
.025 is thicker than .012
.012
what gauge is .012"?
012 = 12 = 1200%
12.5 is not equal to 012 or to 4.
The standard for of 012 is just 12 - without the zero.If you mean .012 (some signs get eliminated in answers.com questions), that already IS the standard form.
ANZ bank in sydney with the bsb of 012 003
.012.
yes
012
.012