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V1M1 = V2M2
(x L)(6.00M) = (0.5 L)(3M)
x = 0.25 liters (250 mls)

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7y ago
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6d ago

To make a 0.5 L of 3 M HCl solution, you would need to dilute the 6.00 M stock solution by a factor of 2. You can calculate the volume needed by using the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. So, you would need 0.25 L of the 6.00 M HCl stock solution to make 0.5 L of 3 M solution.

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Q: What volume of a 6.00 M HCI stock solution would you use to make .5 L of 3M HCI solution?
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