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What volume will 2.00 moles of hydrogen gas occupy at 2.62 ATM of pressure and 300.C?
Wiki User
∙ 8y ago
PV = nRT
V = nRT/P = (2.00 mol)(0.08206 Latm/kmol)(573K)/(2.62 atm)
V = 35.9 liters (to 3 sig. figs.)
Wiki User
∙ 8y ago
Using the ideal gas law, V = (nRT)/(P), where n = moles, R = gas constant, T = temperature in Kelvin, and P = pressure in atm. Plug in the values to find the volume: V = (2.00 moles * 0.0821 L.atm/mol.K * 300 K) / (2.62 atm) = 49.22 L. Therefore, 2.00 moles of hydrogen gas at 2.62 ATM and 300.C will occupy 49.22 liters of volume.
Wiki User
∙ 8y agoThe volume is 35,9 L.
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