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What volume will 4.0 mol of helium gas occupy at 300 K and 2.0 ATM?
Wiki User
∙ 12y ago
You can use the ideal gas law to find the volume:
PV = nRT
V = nRT/P (use R=0.08206 L*atm/mol*K)
= (4.0 mol)*(0.08206 L*atm/mol*K)*(300K)/(2.0 atm)
V = 49.24 L
Wiki User
∙ 12y ago
Amirahmed
450k
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5.64 ATM
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The volume is 13,64 L.
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3.0 atm
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