answersLogoWhite

0

Theta Eridani is at a distance of 120 light years; this means that light reaching us now left it 120 years ago. At that time, there were no cars, no airplanes, no computers, no internet, ...

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

How big is Acamar?

Theta Eridani (Acamar) is a star in the constellation Eridanus.It is about 16 times larger than our Sun.


When a plane mirror is rotated by an angle theta what will be the rotation of the reflected light?

2*theta


What color is acamar star?

Acamar is spectral class A4, which makes it bluish-white.


What waveform is commonly found in light sleepers?

Theta


How old is Acamar?

I think you will be out of luck.Firstly, Theta Eridani (Acamar) is a binary - possibly a multiple star systemSecondly, dating stars ages is a difficult if not impossible task.However, what can be deduced is that Theta Eridani brightest stars have a stellar class of A1 and A4 respectively.All A class stars have a short lifespan of about 1 billion years.Because it has been observed since the ancients - that's 2,000 years in it's favour and it's still fusing hydrogen - another one in it's favour. Basing this with other known stars of similar types I would guess the age at around 500 million years old.


How do you find the circumference of the earth using the arc length formula?

Just did this in my trig class yesterday. Arc length = radius * theta(radians) Circumference of Earth = radius of earth * 2pi Note: The arc length is the circumference of the Earth only in this case because theta is equal to 2pi.


How do solve sin 2 theta - square root of 3 theta- equals 0?

The only real solution is theta = 0For theta < 0 square root of 3 theta is not defined.For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta < 0 square root of 3 theta is not defined.For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta < 0 square root of 3 theta is not defined.For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.The only real solution is theta = 0For theta < 0 square root of 3 theta is not defined.For theta > 0, sin theta increases slower than 3*theta and so the sum is always negative.


If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?

tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2


How would you solve and show work for cos2 theta if cos squared theta equals 1 and theta is in the 4th quadrant?

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1


How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?

cos2(theta) = 1 so cos(theta) = &Acirc;&plusmn;1 cos(theta) = -1 =&gt; theta = pi cos(theta) = 1 =&gt; theta = 0


What are the Pythagorean identities?

There are three of them. Granted this means that there are different variations of all three. I'll show you the variations as well. This is coming straight from my Math 1060 (Trigonometry) notebook. Sorry there is no key to represent the angle; Theta.1. Sin2 (of Theta) + Cos2 (of Theta)= 1Variations: Sin2 (of Theta) = 1- Cos2 (of Theta)AND: Cos2 (of Theta) = 1-Sin2 (of Theta)2. Tan2 (of Theta) + 1 = sec2 (of Theta)Variations: Tan2 (of Theta) = Sec2 (of Theta) -13. 1 + Cot2 (of Theta) = Csc2 (of Theta)Variations: Cot2 (of Theta) = Csc2 (of Theta) -1


What does negative sine squared plus cosine squared equal?

-Sin^(2)(Theta) + Cos^(2)Theta =&gt; Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1