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The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1
The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O
So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g
19.8 g of octane is 114.23/19.8 moles
so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
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∙ 13y ago
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