The products would be zinc chloride and gaseous hydrogen.
zn is ZINC and hcl is HYDROCHLORIC ACID
Zn + 2HCl --> ZnCl2 + H2
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
The reaction is: Zn + 2HCl = ZnCl2 + H2
2Zn(s) + 2HCL (aq) --> 2ZnCl + H2 (g) The reactants are zinc (Zn) and hydrochloric acid (HCl).
zn is ZINC and hcl is HYDROCHLORIC ACID
Zn + 2HCl --> ZnCl2 + H2
7.3 g of HCl.
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
The reaction is: Zn + 2HCl = ZnCl2 + H2
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
2Zn(s) + 2HCL (aq) --> 2ZnCl + H2 (g) The reactants are zinc (Zn) and hydrochloric acid (HCl).
HCl and Zn lack the one carbon and two oxygen atoms that make up CO2 (carbon dioxide) Therefore, they cannot produce carbon dioxide in any condition.
Yes, according to the equation Zn (s) + 2HCl (aq) ----> ZnCl2 (aq) + H2 (g).
H2 and ZnCl2
H (Hydrogen)
Zn + 2HCl >> ZnCl2 + H2