.data 0x10010000
fact: .space 4
.text
.globl main
main: addu $s0, $ra, $0
lui $s1,0x1001
ori $t0,$0,12
ori $t4,$0,1
addi $t1,$t0,-1
mul $t3,$t1,$t0
loop: beq $t1,$t4,slese
addi $t1,$t1,-1
mul $t3,$t3,$t1
j loop
slese: sw $t3,0($s1)
addu $ra,$0,$s0
jr $ra
Pseudo code+factorial
If you really wanted to do this, you could simulate multiplication with repeated addition.
since factorial is for example , the factorial of 5 = 5 (5-1)(5-2)(5-3)(5-4) that means the last number to subtract from 5 is 4 , which is (n-1) ie the factorial of any number is (n-0)(.............)(n-(n-1)) to write this , 5 REM to calculate the factorial of any number 6 DIM fac AS INTEGER LET fac = 1 10 INPUT "enter the number to find its factorial "; a ' variable a 15 FOR b = 0 TO (a-1) 'numbers that will be subtracted from the " a" 20 c= a -b 'each number in the factorial calculation 25 fac = fac * c 'to compute each multiplication in the factorial 30 NEXT b 35 PRINT 'to leave a line 40 PRINT fac 45 END note this due to some unattained raesons works for numbers 0 to 7
/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
Pseudo code+factorial
this is a code for calculating it recursivelly: float Factorial (float n) { if (n<=1) return 1.0; else return n* Factorial(n-1); }
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
i need a pic of cuson
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
Factorials are the product of 1 and all the integers up to the given number. Simply put, 5 factorial or 5! = 5*4*3*2*1
chutia mc,bc bhosdika
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
to find the factorial we declare a variable n and initialize its value to 1 initiate a loop for example a for loop and multiply the numbers upto 5 code:- for(i=1,n=1;i<=5;i++) { n=n*i; }
Factorial is calculated by multiplying be each lower integer. eg factorial 4 (also written as 4!) is 4 x 3 x 2
to find factorials you just multiply the factorial like this. for example 6! you would do 6x5x4x3x2. a little trick of mine is to multiply the previous factorial's answer by the factorial you are trying to make's number like this 6!=5! 5!=5x4x3x2 i hope this was helpful' Dayna,a 10 year old girl
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.