Increase current by either increasing the voltage or decreasing the resistance.
In a series circuit, then yes, there is only one pathway. For example: if one bulb fuses, all the bulbs in the serial circuit will go out. But there are more pathways in a parallel circuit. For example: if one bulb fuses, all the other bulbs in the parallel circuit will still light.
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
The main advantage of a series circuits comes from the fact that when you add a power source, its voltage just gets added to voltage of the circuit. This increase in voltage allows you to easily increase the power going to any electrical device just by adding more sources of voltage. In addition, since current is constant across a series circuit, if you have a collection of devices that all require the same or closely related current, a series circuit instantly gets you there. Finally, on a more economical note, since you only need to wire one loop in series (as opposed to multiple in parallel) you will end up using less wire and spending less on materials to create your circuit. However, if you plan on powering multiple devices at once with the ability to remove any of them at any time or want them to have the same voltage and not the same current, you will have little choice but to concede and use a parallel circuit structure instead.
It really depends on your circuit. I can give just a generic answer for a simple circuit, simple being a voltage source and some resistances. Ampere is a measurement of current. The ratio of voltage to current is resistance (V/I = R or V=IR is a more typical notation). So your question starts with V = 12 and asks how to lower I. I am going to assume V is a constant source, so to lower I all we need to do is increase R. Once we increase R, I will automatically decrease so that the relationship V = IR is held constant. So first determine what you want your I to be, and then add resistors in parallel or series in order to get an R that keeps the voltage constant. or, to put it another way: The current, or Amperage, or the quantity of Amperes, flowing in any simple electrical circuit (at any given voltage) may be lowered or decreased by increasing the resistance in the circuit according to Ohm's law: V = IR, or in this case, its equivalent I = V/R The resistance may be increased, logically enough, by adding a resistor, a device with less than perfect conductance, originally made from carbon or thin wire. Or, if there is a variable resistor (a Rheostat) in the circuit, it may be adjusted to increase its resistance. Electronic devices, such as transistors or vacuum tubes, can also provide variable resistance in a circuit.
A simple method for altering the magnetic flux would be to change the amount of current flowing in the coil or circuit. Generally speaking, more current, more magnetic flux, and vice versa.
increase
In a series circuit, then yes, there is only one pathway. For example: if one bulb fuses, all the bulbs in the serial circuit will go out. But there are more pathways in a parallel circuit. For example: if one bulb fuses, all the other bulbs in the parallel circuit will still light.
The primary difference between a series and a parallel circuit is how many pathways the current has to travel in. Let's look at both of them and see what's up. In a simple series circuit, there is only one path for current. The current must flow through every component in the circuit.
The current measured at any point in a simple circuit will be the same because current is the measure of electron flow through a circuit. The current flowing through any branch of any circuit (or an entire simple circuit) will always be the same at any point.
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
Yes, a battery operated toy has a parallel circuit - the battery is in parallel with the toy. In fact, this is true for any system where there is a single equivalent source and a single equivalent load. While it is true that this is also a series circuit, by Kirchoff's current and voltage laws a simple series circuit is also a simple parallel circuit.
The sum of the currents through the branches of a simple parallel circuit is the current that flows through the voltage source.Kirchoff's current law: The signed sum of the currents in a series circuit is zero. The sum of the currents in the branches represents one effective path, which is in series with the voltage source, so the two effective currents must be the same.
Resistance in series adds together. two 100 ohm resistors in series are equivalent to one 200 ohm resistor. to make an equation out of it ( even though it is simple) you can say: Rtotal=R1+R2+R3...+Rn
In series.
depends on the simple circuit. please describe it.
There isn't anything "scientific" about this simple series circuit. If you've got a variable resistor (a potentiometer) and a diode in series, you have a simple series circuit with the two components in it.
In a simple circuit, lowering the voltage will not cause the resistance to do anything. Lowering the voltage will, however, cause the current to also lower.This ignores temperature coefficient. If there is substantial power involved, a typical bulb, for instance, will grow cooler and its resistance will decrease when you lower the voltage, but that is usually a small effect.