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The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
The gain of a class A, common emitter BJT amplifier, a fairly standard configuration, is defined as collector resistance divided by emitter resistance, or as hFe, whichever is less. Assuming that we are operating in a linear mode, and hFe is not a limiting factor, then the emitter resistance being greater than the collector resistance simply means that the gain is less than one.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
peak inverse voltage :- it is the maximum voltage above which if applied the diode gets destroyed. Here destroyed in the sense the p-n junction gets destroyed due to breakdown voltage, it behaves like a straight conducting wire (which is of no use).
It won't work.
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Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
The generator's voltage regulator will sense the fluctuation. If the voltage goes low more current will be applied to the armature to compensate. If the voltage goes high less current will be applied to the armature to compensate.
If the applied voltage is greater than maximum forward voltage, the diode will get damaged..
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
the winding would burn....
The gain of a class A, common emitter BJT amplifier, a fairly standard configuration, is defined as collector resistance divided by emitter resistance, or as hFe, whichever is less. Assuming that we are operating in a linear mode, and hFe is not a limiting factor, then the emitter resistance being greater than the collector resistance simply means that the gain is less than one.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
peak inverse voltage :- it is the maximum voltage above which if applied the diode gets destroyed. Here destroyed in the sense the p-n junction gets destroyed due to breakdown voltage, it behaves like a straight conducting wire (which is of no use).
It won't work.
The coil will burn out due to having almost double the voltage being applied to it.
Nothing special should happen. What matters for the bulb is the voltage difference between its ends.