java takes command line arguments from user so as to execute the program,that's why we always mention arguments for main() , now java always assumes that the argumetns are of String type which may be appropriately converted to any other type later. that is why we pass string array to hold the command line argumetns supplied by the user.
You can have two String variables (note that String variables are object references) refer to the same String object like so: String str1 = "Hello"; String str2 = str1; Now the str1 and str2 are references for the same String object containing the word "Hello". If you actually want a new String object with a copy of the contents of the original String, you use the String constructor that takes a String argument, like so: String str3 = new String(str1); Now str1 and str3 refer to SEPARATE String objects that happen to contain the same sequence of characters (the word "Hello"). Since Strings objects in Java are immutable, they can be shared without worrying about the contents used by one variable being upset by the use through another variable as might happen with char[] arrays in C or C++ so the first method is probably sufficient for most cases.
In Java, the main() method is typically written something like this:public static void main(String [ ] args)The argument is what is in parentheses, in this case: "String [] args". I believe this can also be written as "String args[]". It refers to parameters received by the Java program from the command line. That is, the user can write, for example:java MyClass info1 info2In this example, "info1" and "info2" will be received by the main method, in the args[] array.
Passing an argument by value means that the method that receives the argument can not change the value of the argument. Passing an argument by reference means that the method that receives the argument can change the value of the incoming argument, and the argument may be changed in the orignal calling method.
The location of a substring within a string in JavaScript can be found using the indexOf() method of the string type. That method will return the placement of a string as a numerical index, starting from 0. The method takes two arguments. The first is the substring you're looking for. In this case "e." The second argument is optional, and it's the "start" argument. If you define it, you define the index from which JavaScript will start looking for the substring. By default, this index is 0 (zero.) If you want to find all of the occurrences of a string using this method, you have to write a loop. To see a working example of that, check out the JSFiddle in the related links. I've also attached a good lesson on JavaScript strings in PDF.
Substring method creates smaller string form bigger string , every time a new string is created but original character array buffer is used. so even if original string is 1G in size and substring is just 1K memory held by substring is 1G because of backed array. this can cause memory leak and prevent original string from garbage collection even if there is no direct reference.
A comma. For example, if your method name is Method1, and you wanted to pass String a, String b, and int c to it, you would do this: Method1(a, b, c);
In Java, the main() method is typically written something like this:public static void main(String [ ] args)The argument is what is in parentheses, in this case: "String [] args". I believe this can also be written as "String args[]". It refers to parameters received by the Java program from the command line. That is, the user can write, for example:java MyClass info1 info2In this example, "info1" and "info2" will be received by the main method, in the args[] array.
string, vector and array do not have a common base class. Overload your function to accept either a string, a vector or an array.
You can have two String variables (note that String variables are object references) refer to the same String object like so: String str1 = "Hello"; String str2 = str1; Now the str1 and str2 are references for the same String object containing the word "Hello". If you actually want a new String object with a copy of the contents of the original String, you use the String constructor that takes a String argument, like so: String str3 = new String(str1); Now str1 and str3 refer to SEPARATE String objects that happen to contain the same sequence of characters (the word "Hello"). Since Strings objects in Java are immutable, they can be shared without worrying about the contents used by one variable being upset by the use through another variable as might happen with char[] arrays in C or C++ so the first method is probably sufficient for most cases.
Passing an argument by value means that the method that receives the argument can not change the value of the argument. Passing an argument by reference means that the method that receives the argument can change the value of the incoming argument, and the argument may be changed in the orignal calling method.
In Java, the main() method is typically written something like this:public static void main(String [ ] args)The argument is what is in parentheses, in this case: "String [] args". I believe this can also be written as "String args[]". It refers to parameters received by the Java program from the command line. That is, the user can write, for example:java MyClass info1 info2In this example, "info1" and "info2" will be received by the main method, in the args[] array.
The location of a substring within a string in JavaScript can be found using the indexOf() method of the string type. That method will return the placement of a string as a numerical index, starting from 0. The method takes two arguments. The first is the substring you're looking for. In this case "e." The second argument is optional, and it's the "start" argument. If you define it, you define the index from which JavaScript will start looking for the substring. By default, this index is 0 (zero.) If you want to find all of the occurrences of a string using this method, you have to write a loop. To see a working example of that, check out the JSFiddle in the related links. I've also attached a good lesson on JavaScript strings in PDF.
parseInt is a method in the Integer class in java and is used to parse string values into integer numbers. ex: int i = Integer.parseInt("10"); After the above line of code, the variable i will be assigned a value of 10 which is the numeric value of the string passed as argument to the parseInt method
public synchronized StringBuffer append(String s)This method will update the value of the object that invoked the method, whether or not the return is assigned to a variable. This method will take many different arguments, including boolean, char, double, float, int, long, and others, but the most likely use on the exam will be a String argument-for example,StringBuffer sb = new StringBuffer("ferrari ");sb.append("car");System.out.println(sb); // output is "ferrari car"public StringBuffer delete(int start, int end)This method returns a StringBuilder object and updates the value of the StringBuilder object that invoked the method call. In both cases, a substring is removed from the original object. The starting index of the substring to be removed is defined by the first argument (which is zero-based), and the ending index of the substring to be removed is defined by the second argument (but it is one-based)! Study the following example carefully:StringBuffer sb = new StringBuffer ("0123456789");System.out.println(sb.delete(4,6));// output is "01236789"public StringBuffer insert(int offset, String s)This method returns a StringBuilder object and updates the value of the StringBuilder object that invoked the method call. In both cases, the String passed in to the second argument is inserted into the original StringBuilder starting at the offset location represented by the first argument (the offset is zero-based). Again, other types of data can be passed in through the second argument (boolean, char, double, float, int, long, and so on), but the String argument is the one you're most likely to see:StringBuffer sb = new StringBuffer ("ferrari");sb.insert(4, "---");System.out.println( sb ); // output is "ferr---ari"
The first thing to note about constructor overloading is that Java creates a no argument constructor for you if and only if you have not typed a constructor yourself. Every class has a constructor even abstract ones (default no argument constructor). Abstract constructors are always executed. To overload a constructor you can do the following: class Test { String name; Test(String n) { name = n; System.out.println("Constructing Test Object named: " + name); } } In the case above we are overloading the default no argument constructor with a constructor that takes a String parameter. You can write you own no argument constructor as follows: class Test { Test() { System.out.println("Constructing Test Object"); } } To override our own no argument constructor we do this: class Test { Test() { // our no argument constructor System.out.println("Constructing Test Object"); } String name; Test(String n) { // overloading our no argument constructor with this // constructor that take a String parameter name = n; System.out.println("Constructing Test Object named: " + name); } }
Substring method creates smaller string form bigger string , every time a new string is created but original character array buffer is used. so even if original string is 1G in size and substring is just 1K memory held by substring is 1G because of backed array. this can cause memory leak and prevent original string from garbage collection even if there is no direct reference.
In Java, the main() method is typically written something like this:public static void main(String [ ] args)The argument is what is in parentheses, in this case: "String [] args". I believe this can also be written as "String args[]". It refers to parameters received by the Java program from the command line. That is, the user can write, for example:java MyClass info1 info2In this example, "info1" and "info2" will be received by the main method, in the args[] array.