Assuming a shunt-fed motor, it means the rotor would stop generating a back-emf and it would also stop generating any torque. The current would rise until limited by the resistance of the rotor, but before that the circuit-breaker would operate.
speed will increase
The field current of a dc motor provides the magnetic field that allows the motor to develop a torque when current flows through the armature..
To start an induction motor we have to excite field. The excitation is done by connecting the DC supply to the field winding's.
Assuming a shunt-fed motor, it means the rotor would stop generating a back-emf and it would also stop generating any torque. The current would rise until limited by the resistance of the rotor, but before that the circuit-breaker would operate.
L , F and A L - Line (connected to Supply) F - Field (connected to field of dc motor) A - Armature (connected to armature of DC motor) that's y it is called 3 point
Starting of the synchronous motor using the DC generator creates a magnetic field.
Because tests on a dc motor are always done using dc.
when the field winding of a running dc shunt motor suddenly breaks open the motor fails to run because in the motor the stationary winding is armature and rotatory is field winding
It depends on both the wiring of the motor and what if any residual magnetic field remains in the field windings. If there is some residual field, you will get some volts, but not many. If the motor has permanent magnets, it is effectively a dynamo.
a motor Will do work by consuming power a generator is just the opposite
Shunt Motor
when the field winding of dc motor opens the flux is zero so the speed is inversely propotional to speed ,so motor runs at dangerous speed...........