The correct term is 'current', not 'amperage'. The answer is that nothing will happen to the resistance. Having said that, changing the resistance will cause current to change for a fixed value of voltage.
Resistance is determined by the length, cross-sectional area, and resistivity of a material. Resistivity is affected by temperature, so resistance is also therefore indirectly affected by temperature. Only by changing one of these variables will the resistance change.
Since the ratio of voltage to current will tell us what the resistance of a circuit happens to be (it's not affected by that ratio) for a particular ratio, the ratio will increase (as per your question) if the resistance increases. But it's not the ratio that's affecting resistance, its the resistance affecting the ratio!
According to ohms law, V = IR, where V=voltage I= current R = resistance the above formula can also be written as I = V/R, here, resistance is inversely proportional to current. In other words, as resistance increases, current decreases.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
A load is anything that draws current from a source of potential difference. A 'heavy' load will draw a larger current than a 'light' load. A resistor can certainly be used as a load. A low resistance will draw a larger current than a higher resistance and, so, a low resistance represents a high load while a high resistance represents a low load.
According to ohms law (V=IR)if voltage is increased the current also increases keeping the resistance same .In other words, to keep values on the both sides of equal sign current must increase with the voltage when the resistance is constant. For example: if R=1 and V=2 then I=2 and if voltage is increased to 4 then current also increases with voltage to 4.CONCLUSION:V IS DIRECTLY PROPORTIONAL TO I KEEPING THE R CONSTANT
If ther is a resistive load we got curent and voltage in phase. If the load is inductive curent lags behind the voltage. IN THIS CASE THER IS BOTH LOAD THAT MEANS CURENT WILL LAG BEHIND THE VOLTAGE
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
v = i*RIf i goes down then R must go up (assuming v remains the same).AnwerCompletely impractical question. Resistance is not directly affected by voltage or current, so what you describe won't happen!
The correct term is 'current', not 'amperage'. The answer is that nothing will happen to the resistance. Having said that, changing the resistance will cause current to change for a fixed value of voltage.Resistance is determined by the length, cross-sectional area, and resistivity of a material. Resistivity is affected by temperature, so resistance is also therefore indirectly affected by temperature. Only by changing one of these variables will the resistance change.Since the ratio of voltage to current will tell us what the resistance of a circuit happens to be (it's not affected by that ratio) for a particular ratio, the ratio will increase (as per your question) if the resistance increases. But it's not the ratio that's affecting resistance, its the resistance affecting the ratio!
The amperage to the motor will go higher.
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
Ohms law states current is directly proportional to the volts and inversely proportional to the resistance of the circuit. What will happen if you apply 5 volts to a 12 volt, device the amperage will drop proportionally. The wattage output will drop from 168 watts to 30 watts. The device fed with 12 volts and has an output of 168 watts will draw 14 amps. This calculates the resistance to be .85 ohms. The same device fed with 5 volts reduces the amperage to 6 amps resulting in an output wattage of 30 watts. Since the resistance remains the same no mater what, the only way to move the amperage value is to vary the voltage level.
Nothing, but the current will increase.
Current draw would increase proportionally, heating up the wiring and wearing more on the load pulling the power.
The current will also increase. This can be proved by using ohms law, V=IR --> I=V/R, as the resistance is constant the R can be replaced by the number 1 therefore I=V/1 or I=V, hence if the voltage increases the current must also increase.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.