If ther is a resistive load we got curent and voltage in phase. If the load is inductive curent lags behind the voltage. IN THIS CASE THER IS BOTH LOAD THAT MEANS CURENT WILL LAG BEHIND THE VOLTAGE
When an AC circuit contains both resistance and inductance the current and voltage will be in phase. This means having waveforms that are of the same frequency and that pass through corresponding value.
A 'purely capacitive' circuit is a theoretical, or 'ideal', circuit, in which the resistance and inductance of the circuit is ignored, and in which the load current theoretically leads the supply voltage by exactly 90 electrical degrees. It is often used as a means of introducing students to the behaviour of 'real' a.c. circuit which contain contain resistance and inductance, as well as capacitance.
self-induction."According to Lenz's law,[6]a changing electric current through a circuit that contains inductance, induces a proportional voltage, which opposes the change in current (self-inductance). The varying field in this circuit may also induce an e.m.f. in neighbouring circuits (mutual inductance)." - Wikipedia
a circuit with no resistance or zero resistance can be considered as open circuit in which the current is zero. without resistance the circuit just becomes open ()
In a circuit , current is inversely proportional to the resistance.
When an AC circuit contains both resistance and inductance the current and voltage will be in phase. This means having waveforms that are of the same frequency and that pass through corresponding value.
a. the current and voltage in phase
Current lags voltage in an inductive circuit. The angle by which it lags depends on the frequency of the AC, and on the relative size of the inductance compared to the resistance in the circuit.
A 'purely capacitive' circuit is a theoretical, or 'ideal', circuit, in which the resistance and inductance of the circuit is ignored, and in which the load current theoretically leads the supply voltage by exactly 90 electrical degrees. It is often used as a means of introducing students to the behaviour of 'real' a.c. circuit which contain contain resistance and inductance, as well as capacitance.
A 'purely capacitive' circuit is a theoretical, or 'ideal', circuit, in which the resistance and inductance of the circuit is ignored, and in which the load current theoretically leads the supply voltage by exactly 90 electrical degrees. It is often used as a means of introducing students to the behaviour of 'real' a.c. circuit which contain contain resistance and inductance, as well as capacitance.
self-induction."According to Lenz's law,[6]a changing electric current through a circuit that contains inductance, induces a proportional voltage, which opposes the change in current (self-inductance). The varying field in this circuit may also induce an e.m.f. in neighbouring circuits (mutual inductance)." - Wikipedia
Voltage=V in Volts Current=I in Amps Resistance=R in Ohms Inductance=F in Henry Capacitance=C in Farads
An ideal inductor does not oppose the steady flow of current because it has no resistance. But it opposes changes in the current and the voltage across the inductor is the rate of change of current (in amps/second) times the inductance in Henrys, which is how inductance is defined. So when a battery is connected across an inductor the initial rate of rise of the current is V/L amps/sec, where L is the inductance, and it continues to rise until limited by any resistance in the circuit.
The voltage across the inductance alone will be(value of the inductance) times (the rate at which the current through it changes)
Voltage=V in Volts Current=I in Amps Resistance=R in Ohms Inductance=F in Henry Capacitance=C in Farads
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
This question is nonsense because a dc supply has no "frequency".In any circuit supplied by direct current, the current always flows in the same direction from the point in time when the current is switched on until the point in time when it is switched off.Comparing a circuit that has both resistance and inductance with a circuit that only has resistance:Until a steady-state level of current flow has been reached from the point in time when the current is switched on, the current will rise at a slower rate in the circuit that has inductance compared with the circuit that only has resistance, because the inductance impedes the build-up of current.Then, when the current is switched off, the flow of current will stop instantly in the circuit which only has resistance but in the circuit that has both resistance and inductance, the sudden drop in current will cause a high voltage potential to be developed across the inductor which will dissipate slowly back down to zero through its own resistance.However, if a spark-gap is connected into the circuit across the winding of the inductor - and its inductance is sufficiently large and the spark-gap is sufficiently small - when the current is switched off the high voltage potential across the inductor will generate a spark to appear across the spark-gap that will "zap" the high voltage almost instantly. That is the principal of operation of the spark-ignition coil used to ignite the gas/air mixture in a gas engine using "spark-plugs".