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What will happen to the wavelength if the frequency is decreased?
Wiki User
∙ 14y ago
the wave length will increase
Wiki User
∙ 14y ago
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What happened to the wavelength and frequency when you increased the rate at which the spring toy moved left and right?
The wavelength decreased and the frequency increased.
What happens to the wavelength of a wave if the frequency is decreased?
In this case, the wavelength increases. The wavelength, multiplied by the frequency, is equal to the speed of the wave - and in most types of waves, the speed is more or less independent of the frequency.
What will happen to the wavelength of a wave if the frequency is left unchanged?
If the frequency stays the same, then the wavelength stays the same.
What happens to frequency of a wave when the wavelength is decreased and when the wavelength is increased?
When wavelength decreases, frequency increases, and when wavelength increases, frequency decreases. The product of (wavelength) times (frequency) is always the same number ... the speed of the wave. So when one of them changes, the other one must change in the opposite direction in order for their product to remain unchanged.
What would happen to the wavelength of a wave if the frequency is halved?
The wavelength would double.
What happened to the wavelength and frequency when you increased the rate at which the spring toy moved left and right?
The wavelength decreased and the frequency increased.
What happens to the wavelength of a wave if the frequency is decreased?
In this case, the wavelength increases. The wavelength, multiplied by the frequency, is equal to the speed of the wave - and in most types of waves, the speed is more or less independent of the frequency.
What happens to the frequency of a wave when the wavelength is decrased and why?
The freequency of a wave is increased when the wavelength is decreased. This is because the product of the frequency and the wavelength are a constant that determines the speed of the wave c=fw.
What happens to the wavelength of a wave when the energy is increased?
If you are talking about an electromagnetic wave; energy is proportional to frequency (E=hf), and frequency is inversely proportional to wavelength (wavelength equals velocity divided by frequency). So when the wavelength is increased, the energy is decreased.
What will happen to the wavelength of a wave if the frequency is left unchanged?
If the frequency stays the same, then the wavelength stays the same.
What happens to frequency of a wave when the wavelength is decreased and when the wavelength is increased?
When wavelength decreases, frequency increases, and when wavelength increases, frequency decreases. The product of (wavelength) times (frequency) is always the same number ... the speed of the wave. So when one of them changes, the other one must change in the opposite direction in order for their product to remain unchanged.
What would happen to the wavelength of a wave if the frequency is halved?
The wavelength would double.
What happens to the amount of energy that can be carried as the wavelength decreased?
As wavelength decreases, energy increases, because the two are inversely related. Conversely, as wavelength decreases, frequency increases.
How is the wavelength related to frequency for waves moving at a constant speed?
Whatever the wavelength and frequency happen to be, their product is always equal to the speed.
What happens to frequency when you double wavelength?
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
What happen to the speed when frequency and wavelength change?
It would change, depending on how much the frequency and the wavelength changes. It varies based on v = fλ.
If a wave is moving at a constant speed and the wavelength is doubled what will happen to the frequency?
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
