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Power transformers have an impedance (Z) rating that is listed in %. So the nameplate might state 5% Z for example. What this means is that when the secondary conductors are bolted together then 5% of the rated primary voltage is applied and will generate 100% current in flow in the secondary. Example: you have a 75KVA Delta-Wye 5% Z transformer with a 480V primary rating and 208/12 secondary rating. The amp rating of the secondary is 208A [75,000/(1.732x208)] So if you applied 24VAC to the primary with the secondary bolted together with busbar then you would have 208A of current flow.
Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is. Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this. As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.
There are two diode ratings. One is the forward current rating, and the other is the reverse breakdown voltage rating. The forward current rating is the maximum current that the diode can conduct before failing, and the reverse breakdown voltage rating is the maximum reverse voltage that can be applied before failing. Of course, the reverse voltage rating has a different meaning in a zener diode, but this answer applies to ordinary diodes.
The voltage rating of a capacitor tells the user how much voltage the capacitor can withstand. If a user exceeds this voltage, the capacitor's dielectric may be damaged and destroyed.
It depends on the voltage rating.
15.5kv
It has the highest voltage rating to bring it to the primary supply. This supply is at 17.5kV for 15kV, 24kV for 20kV.
The amp rating for a 100VA transformer will vary depending on the actual voltage of the transformer. Transformers have both a primary and a secondary voltage.
Input and output voltages, maximum current rating, often expressed in VA or kVA as the voltage rating times the current rating. Operating frequency is the next important parameter because if the frequency is lower, the voltage must be reduced in proportion.
True. The voltage rating of a fuse must be greater than the circuit voltage.
Power transformers have an impedance (Z) rating that is listed in %. So the nameplate might state 5% Z for example. What this means is that when the secondary conductors are bolted together then 5% of the rated primary voltage is applied and will generate 100% current in flow in the secondary. Example: you have a 75KVA Delta-Wye 5% Z transformer with a 480V primary rating and 208/12 secondary rating. The amp rating of the secondary is 208A [75,000/(1.732x208)] So if you applied 24VAC to the primary with the secondary bolted together with busbar then you would have 208A of current flow.
Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is. Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this. As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.
A larger voltage rating: yes, of course. A larger size rating: these are not normally related to the voltage rating, which is separate. A larger physical size: normally this means a greater voltage, but again, they are not directly related to the voltage rating. Size has nothing to do with voltage. Battery voltage is controlled by the number of cells in the battery. Plate size affects current delivery.
Yes, it will work fine. The downside is that it might cost more than one of the lower voltage rating, or that it might be physically larger. A capacitor voltage rating is a maximum, so any lower voltage is also acceptable.
There are two diode ratings. One is the forward current rating, and the other is the reverse breakdown voltage rating. The forward current rating is the maximum current that the diode can conduct before failing, and the reverse breakdown voltage rating is the maximum reverse voltage that can be applied before failing. Of course, the reverse voltage rating has a different meaning in a zener diode, but this answer applies to ordinary diodes.
The voltage rating of a capacitor tells the user how much voltage the capacitor can withstand. If a user exceeds this voltage, the capacitor's dielectric may be damaged and destroyed.
It depends on the voltage rating.