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How many kcal are produced when 32.0g of CH4 react? CH4+2O2->CO2+2H2O+218 kcal
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
Hydrocarbons such as methane burning in oxygen is an example of oxidation and also combustion.
6 molecules of oxygen are needed to react with 3 methane molecules as one molecule of oxygen ( O2) are needed for methane gas.
Take the balanced equation. CH4+2O2---->CO2+2H2O.So 2.8mol of CH4 need 5.6mol of O2.So O2 is limitting factor
CH4 + 2O2 gives CO2 and 2H2O.So 16g of CH4 react with 64g of O2.So 24g react with 96g of O2
The hydrocarbons in the fuel react with oxygen to form CO2 plus water (H2O). The simplest hydrocarbon is methane which is the biggest part of natural gas, formula CH4. So CH4 + 2O2 ---- CO2 + 2H2O
How many kcal are produced when 32.0g of CH4 react? CH4+2O2->CO2+2H2O+218 kcal
methane rapidly combines with oxygen to form carbon dioxide and water, releasing lots of heat. it's called combustion.-------------------------------------------------------------------------CH4 + 2O2 = CO2 + 2H2O + heat
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
CH4 + 2O2 → CO2 + 2H2O Methane + Oxygen → Carbon dioxide + Water
Hydrocarbons such as methane burning in oxygen is an example of oxidation and also combustion.
CH4 is non polar and water is polar.So they do not mix up
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
Carbonic acid. The reaction is: . H2O + CO2 -----> H2CO3
Hydrogen combines with oxygen at the completion of a combustion reaction to form water. The following is the balanced equation for the combustion of methane (CH4). CH4 + 2O2 ---> CO2 + 2H2O
Take the balanced equation CH4+2O2---->CO2+2H2O.So according to it 40g of O2