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In 5 years, the population will increase by 5 percent (1 percent each year for 5 years), so the overall population will be 1.05 times the current population. Therefore, the population in 5 years will be 8500 * 1.05 = 8925.
population has increased over 27% over the past 5 years. We are seeing increases in population due to males taking viagra.
27% for the last 5 years
They live for 5-7 years.
The population of communities in Canada is taken every 5 years. In 2001 Thunder Bay's population was 121 986. In 2006 Thunder Bay's population was 122 907. An increase of 0.8% over the 5 year span.
5 Years
population = 30 × 3^(20÷5) = 30 × 3⁴ = 2430
The population will double when it reaches 100% growth, which is a 20% increase five times. Therefore, it will take 5 years x 5 = 25 years for the population to double.
The population density of sand crabs in that section of the beach is 3 sand crabs per square meter. This is calculated by dividing the total count of sand crabs (45) by the area of the section (5 meters * 3 meters = 15 square meters). Therefore, 45 sand crabs / 15 square meters = 3 sand crabs per square meter.
5,000,000,000,000
27% for the last couple of 5 years
Ann Beach is 5'.