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If the "you" is supposed to represent an "I", then the answer is Conceited.
D D# E C E C E C C D D# E C D E BD C D D# E C E C E C AG F# A C E D C A D D D# E C E C E C C D D# E C D E B D C C D C E C D E C D C E C D E C D C E C D E E B D C #=sharp
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yes it is it it or that word is the twinny word...
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E-E-F-G-G-F-E-D-C-C-D-E-E-D-D E-E-F-G-G-F-E-D-C-C-D-E-D-C-C D-D-E-C-D-E-F-E-C E-E-F-G-G-F-E-D-C-C-D-E-D-C-C Thank you.
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The general formula for the number of combinations of r things chosen from n different things is C(n,r) = n!/ r!(n-r)! How many ways can 5 players be chosen from a team of 13? (Where the order you choose the players does not matter). So C(13,5) = 13!/5!(13-5)! Or 1,287
C C C D E E E D C D E C E E F G G F E F G E C C D E E D C D E C G G C C C D E E E D C D E C
C(^), e, c b a g e, c c e, e, e d d c, e g, c c e, e, c d, d, c. E, g g e e g, f f f d b, g, c c e, e, c d, d, c. C(^) g c b g b a d a g. C c e, e, c d, d, c. (etc.)