It depends... If the voltage were applied externally, like to fingers or toes, etc. basically nothing. If the voltage were applied to the tongue, you would feel a tingling sensation, nothing more. If it were applied with electrodes inserted through the chest directly to the heart muscle, it could stop your heart, killing you! It's not the volts that cause damage or pain, its the amps. The higher the voltage, the higher the amps. Also, if the electrodes touch moist tissue such as your tongue, the saline moisture conducts better, causing higher current. If the current gets high enough, tissues start to heat, and enough can cause tissue destruction. 7.5 volts is not high enough to do that, given the resistance of human tissue. But, even low current, if it flows through a muscle, can cause the muscle to contract uncontrollably. This is why even a small current through the heart is trouble. Unless you deliver the current directly to the heart muscle, it takes much higher voltage. If you grab an electrode with each hand, for instance, some current would flow through the heart, but because the skin resistance is so high, it takes several dozens of volts before the heart would be endangered.
If the amperage is high enough, yes.
60 and 100 watt in series then the 60 watt will have the biggest voltagedrop.In parallel they are the same.Using a voltage of 120 volts, the 60 watt lamp would have 75 volts across it and the 100 watt lamp would have 45 volts across it in a series circuit, bringing the total to 120 volts.
Watt's are a product of volts and amps. You need to now what those are to find the wattage of a circuit and then multiply by 75%.
At 120 Volts you would draw about 42 amps. At 240 Volts it would be about 21 amps. For 120 Volts you would need 6 AWG and for 240 Volts you would need 10 AWG.
10 AWG in copper.
250
Volts. 12.6 volts = Full Charge 12.4 volts = 75% Charge 12.2 volts = 50% Charge 12.2 volts = 25% Charge
Fully charged battery should have 12.6 volts. 75% charged 12.4 volts, 50% charged 12.2 volts, & 25% charged 12.0 volts.
100% charge = 12.6 volts 75% charge = 12.4 volts 50% charge = 12.2 volts 25% charge = 12.0 volts
It reads what the voltage is so maybe the voltage source is 75 volts. Without stating what the voltage is suppose to be it is hard to give an answer to this question.
12.6 volts = 100% Charge 12.4 volts = 75% 12.2 volts = 50% 12.0 volts = 00%
12.6 volts at 100% charge 12.4 volts at 75% charge 12.2 volts at 50% charge 12.0 volts at 25% charge
If the amperage is high enough, yes.
12.6 volts 100% charge 12.4 volts 75% charge 12.2 volts 50% charge 12.0 volts 25% charge Any less and the battery is essentially dead.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
As read from the battery with a digital volt meter with engine off. 12.6 volts = 100% charge 12.4 volts = 75% charge 12.2 volts = 50% charge 12.0 volts = 25% charge
#8 copper