Want this question answered?
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.
Marik the Monster's face started to mutate when full moon came.
it depends on the codon spcified. The tRNA will have the complementary strand along with an amino acid, for which is specified by the mRNA. if the mRNA codon was "CGA" the tRNA codon would have an amino acid and the complementary codon of "GCU"
The new codon would code for glutamine. Translation would continue until the ribosome encountered another stop codon or ran out of messenger RNA to translate.ExplanationUAG is an RNA codon. If the uracil (U) in the codon were changed to cytosine (C), the codon would be CAG, which codes for the amino acid glutamine.
AGT codes for the amino acid serine and CTT codes for the amino acid leucine.
an anti-codon is a code for an amino acid found on protein
Methionine is always the first amino acid in a protein, therefore the codon for Met would signal the beginning of protein synthesis. This codon is AUG.
The major casein fraction in goat milk has higher leucine concentrations than the major casein fraction in cow's milk. This would suggest that although the proportion of the five major proteins that make up goat milk vary from sample to sample, it would typically contain as least as much leucine as cow's milk and therefore be inappropriate for those with leucine sensitivity.
The anticodon sequence would be GAG-UUC-ACG-AAG.
This is a stop codon. The polypeptide would be completed here and would detach from the ribosome.
hydrophobic
It will be AGU.