HNO3 is a strong acid, which means it dissociates completely. This means you don't have to set up an equilibrium scenario; you can just go with the given molarity as also being the concentration of hydrogen ions [H+]. So, pH = -log(0.00884), which is about 2.05.
The pH of a neutral solution is 7 and the concentration of H+ or H3O+ in the solution would be 1.0 X 10-7.
pH is the acidity. low pH is more acid, while high pH is more basic.
NaOH is a base so it will produce a pH above 7.
An acidic solution has a pH under 7 and a basic solution has a pH over 7.
a buffer is wrong, it is basic or alkaline, depending on the choices
- log(0.01 M HNO3) = 2 pH =====
pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions. HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also. So, pH = -log10[5] = -0.699 which indicates an extremely strong acid.
pH = -log[H+] pH = -log[1.6 × 10-3] pH = 2.8
Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )
Neutral solution: pH =7Acidic solution: pH7.
A solution with a pH of 7 compared to a solution with a pH of 9 would be more acidic.
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A neutral solution would have a pH of 7.
If nitric acid (HNO3) is added to water, it decreases the concentration of hydroxide ions in solution. This is because nitric acid semi-strongly dissociates in water, following this chemical reaction: HNO3(aq) + H2O(l)-->NO3-(aq) + H3O+(aq) The hydronium ions that are created in this reaction then react quickly with the hydroxide ions in the water, as shown in this chemical equation: H3O+(aq) +OH-(aq) --> 2H2O(l) This results in fewer hydroxide ions existing in solution.
pH= -log [H+] = -log [1] = 0
It would be expected to be near neutral, because it is produced by reacting nitric acid (HNO3) with sodium hydroxide (NaOH). It represents the salt product of a strong acid and a strong base, so its pH in solution will be very near 7.
pH = 0-7 acidic solution pH = 7 neutral solution pH = 7-14 basic solution