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Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH.

1.32 grams HNO3 (1 mole HNO3/63.018 grams)

= 0.020946 moles nitric acid

-------------------------------------

Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters )

Molarity = 0.020946 moles HNO3/0.750 Liters

= 0.027928 M HNO3

----------------------------------finally,

- log(0.027928 M HNO3)

= 1.55 pH

==========( could call it 1.6 pH )

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12y ago
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-0.121

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andiswanxonyeka

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2y ago

1.32

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Q: What is the pH of a solution that contains 1.32 grams of nitric acid dissolved in 750 milliters of water?
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