pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions.
HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also.
So,
pH = -log10[5]
= -0.699
which indicates an extremely strong acid.
The pH of 15 mL of 0.0045 M HNO3 is 2.35. The pOH is 11.7. When a solution has a pH under 7, it is said to be acidic.
Take the minus log value.So pH is equal to 1.
about 11.2 pH
pH = 1
1.64
pH= -log [H+] = -log [1] = 0
Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )
- log(0.01 M HNO3) = 2 pH =====
pH = -log[H+] pH = -log[1.6 × 10-3] pH = 2.8
The pH value of those solutions depends on the concentration and the temperature. Generally, solutions with higher concentrations of acids have lower pH values.
pH= -log [H+] = -log [1] = 0
Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )
pH = pKa - log([HA]/[A])[HA] = concentration weak acid NH4+ and [A] = concentration of weak base NH3 Before HNO3 addition [HA]= 6.0 mmol NH4+ in 100 ml => after: [HA]= 6.0+5.3 mmol NH4+ in 101 mlBefore HNO3 addition [A]= 11.5 mmol NH3 in 100 ml => after: [HA]= 11.5-5.3 mmol NH3 in 101 mlThus: (notice that pH of buffer is independent from a large range of dilution)pHbefore = 9.24- log10(6.0/100 / 11.5/100) = 9.24 - log10(6/11.5) = 9.52and:pHafter = 9.24 - log10(11.3/101 / 6.2/101) = 9.24 - log10(11.3/6.2) = 8.98
- log(0.01 M HNO3) = 2 pH =====
pH = -log[H+] pH = -log[1.6 × 10-3] pH = 2.8
the lower the pH the stronger the acid
The pH value of those solutions depends on the concentration and the temperature. Generally, solutions with higher concentrations of acids have lower pH values.
This depends on the mass of calcium carbonate.
7
HNO3 is nitric acid. De[emdimng on its level of concentration it can vary from '0' (very concentrated ; 16M) to '3'. ) low concentration (dilute ' say 0.6 M).
pH is an INTENSIVE property as it does not depend on the amount of material present. The pH of 1 ml of solution x is the same as the pH of 100 ml of solution x.
It actually depends on what type of shark it is, and its speed it.