Homozygous dominant would be all Capital letters.
Homozygous recessive would be all lower case letters.
So...in basic color genetics for horses:
A homozygous recessive horse would be aaee
A homozygous dominant horse would be AAEE
t t T Tt Tt
T Tt Tt
A heterozygous red short plant.
Edited answer:
It will result into a heterozygous red & tall plant with genotype RrTt.
You would get a hybrid tall plant.
recessive
Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.
the tall plant must be heterozygous
Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.
Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.
Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.
Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.
Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.
TT for the homozygous tall parent, tt for the homozygous short parent and Tt for the heterozygous offspring.
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
The offspring will look more like the mom but they will have mid hair.
recessive
Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.
I assume you mean heterozygous dominant tall and short is recessive.T = tall.t = shortTt X tt (called a test cross )1/2 Tt-----------------------heterozygous dominant1/2 tt-----------------homozygous recessive
the tall plant must be heterozygous