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If these atoms are loose unities, not bonded in a molecule, it would be about 22 dm3 at 0oC and standard pressure (STP). If the atoms would have formed gas molecules, e.g. CO2 or SF6, the answer would be different, because 6.02 x 1023 molecules always take in a volume of about 22 dm3 at STP. But with CO2 you would have then 18 x 1023 atoms because there are 3 atoms in one molecule.

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12y ago
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11y ago

helium molecule is mono atomic. 6.023 x 1023 atoms of helium occupy 22.414 liters at STP.

So 4.02 x 1022 atoms will occupy 1.5 liters at STP

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8y ago

One mole of any gas at STP occupies about 22.4 litres. 6g of helium is 1.5 moles so it would occupy 1.5 x 22.4 = 33.6 litres.

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8y ago

6.00 g of helium gas at STP equals 33,6 litres.

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15y ago

22.4L

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Q: What would be the volume of 6.00 g of helium gas at STP?
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