It wil be on
Disconnecting a wire from a battery would break the circuit. If the battery was powering a bulb, the lamp would go out.
Nothing much will happen except the same bulb will not blow..
An example of a closed electrical circuit would be a battery to a light bulb, the only source of power being the battery and no other input from an outside source. Like video cameras in a store they would be considered a closed circuit surveillance system so long as the signals stay inside the store and don't leave to a remote location.
A D cell battery supplies nominally 1.5V. Connecting a 6V supply in it's place would supply an extra 4.5V and could potentially damage the circuit components.
A battery or eletrical generator would do that.AnswerYour question should be rephrased. You do not 'give power' to a circuit. 'Power' is simply a rate -the rate of doing work.
Nothing will happen to circuit..... as usual the circuit would be supplying 220v(if india) and certain current...but there is no bulb to consume power...
You would short out the battery. If it was a car battery capable of 300 amps and the wire was big enough, the battery could explode.
would discharge in 18 hours
V = IR, so if you double the voltage without changing the resistance, the current will also double.
A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
Nothing. The reason a circuit works is that there is an imbalance between the positive and negative (cathode and anode) ends of the battery. two positive ends wouldn't move anything.
It would depend on the circuit diagram. In some cases, the circuit would be incomplete (simplest case is a battery with a wire attached to just one terminal).Parallel branches that have a connection to the battery without going through other branches are independent of each other. Say you have two parallel branches and a battery. If you short circuit one of the branches, the other branch will not be affected but the battery will be (current through the battery would decrease because taking out a parallel branch increases resistance).In short, it would depend on the circuit diagram. Note that for a nanosecond, there would be current in an open circuit, but after this brief time there would be no current flow in the segment of the circuit that has been shorted.
Disconnecting a wire from a battery would break the circuit. If the battery was powering a bulb, the lamp would go out.
The circuit will de-energize.
Adding a seound battery to a series circuit will increase the voltage, and require less current to keep the lights (if there are any on) as bright. Say you have a 6v battery, then you add another 6v battery. the voltage of the circuit would be 12v
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
Flashlight by light, battery, circuit, a hood and a reflective cup, circuit storehouse, switch, etc, the basic principle is the current from the battery, and then to the circuit, after adjusting circuit voltage and current, and then output to the light source for lighting.