Want this question answered?
the equilibrium will be shifted backward so that the dissociation of NaHSO4 will decrease (less H+)
Le Chetalier's principle predicts a system at equilibrium will change to adapt. If more products are added, the system will react to tend to negate that change, so more reactants would form.
Suppose: B- is symbol for any (soluble) base.Equilibrium of a base when diluted in water:B- + H2O HB + OH-Equilibrium constant:Keq = [HB] * [OH-] / [B-] * [H2O]The base dissociation contant is defined by:KB = [HB]*[OH-]/[B-]So, KB = Keq*[H2O] = Keq*55.6 mol/L
sex
what would happen if you added silver ion to FeCl-4
The concentration of products would increase. apex
more N2 and O2 would form
The ionic compounds exist as solid crystals or Lattice, when such compounds are added to water crystals break down into ions ,it is dissociation (breaking) of lattice.
The concentrations of reactants and products are modified.
If the added substance is a reactant, the equilibrium shifts toward products. If it is a product, it moves towards reactants.
If the added substance is a reactant, the equilibrium shifts toward products. If it is a product, it moves towards reactants.
the equilibrium will be shifted backward so that the dissociation of NaHSO4 will decrease (less H+)
Le Chetalier's principle predicts a system at equilibrium will change to adapt. If more products are added, the system will react to tend to negate that change, so more reactants would form.
which two things can happen when heat is added to a liquid?
Suppose: B- is symbol for any (soluble) base.Equilibrium of a base when diluted in water:B- + H2O HB + OH-Equilibrium constant:Keq = [HB] * [OH-] / [B-] * [H2O]The base dissociation contant is defined by:KB = [HB]*[OH-]/[B-]So, KB = Keq*[H2O] = Keq*55.6 mol/L
sex
if its complete dissociation, then the products would be a salt and water, which means the pH is 7 or neutral. OMG, if the pH is currently 4 then [H+] = 1.0 e-4 M (pH = -log[H+]) if you add 0.003 moles then 1.0e-4 M +.003 M = .0031 M (Since the strong acid HCL completely dissociates in aq solution) pH = -log [.0031M] = 2.51