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What would happen to the pH value if you mix equal amounts of a strong acid with a strong base?
Wiki User
∙ 13y ago
The pH value will be reduced to nearly 1 with the effect of neutralisation and the end products of salt and water.
Wiki User
∙ 13y ago
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Why is the enthalpy change of neutralisation equal to -57.2kJ mol-1?
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
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