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The rate would be four times larger. Impossible.
It will decrease by half.
Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
The reaction would shift to balance the change
the balloon would probably put on a jumper
The rate would be four times larger. Impossible.
The rate would be four times larger. Impossible.
It will decrease by half.
This rate law suggests its rate to be direct proportional to H2 concentration, thus halving this would implicate a halved reaction rate.
The rate would also behalved
The reaction rate would decrease
Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
The rate would be one-fourth. Correct on Apex.
The wavelength would double.
circumference would be halved, area would be one fourth of original , andvolume would be one eighth of original.
The one with the larger mass would pull the halved mass one toward it
It would take a longer amount of time for the substrate to be fully broken down into its final products.