The cell will shrinks as the fluid inside the cell will flow out due to osmosis.
D carot will shrink bcos it is surounded by an hypertonic solution
It will die.
they would be in a hypertonic solution, so they would shrivel and die
The plant cell would shrink but remain its shape.
It would shrivel up and die, because water would flow out of the cell.
A cell immersed is a hypertonic solution will tend to lose water to the solution and shrink.
it will shrink
D carot will shrink bcos it is surounded by an hypertonic solution
It will die.
I will take the cell to be animal cell. The hypertonic solution is taken as hypertonic saline solution. The cell will shrink in that case. There will be loss of water to the exterior of the cell. The biochemical cellular functions will be adversely affected. The cell may die if the solution is sufficiently hypertonic.
The solution will gain water from the fish, till the fish shrinks, and if the fish is not removed from the solution, the fish will die
You need dayan 2 hours
they would be in a hypertonic solution, so they would shrivel and die
The plant cell would shrink but remain its shape.
When placed in an isotonic solution nothin will happen to the cell, but when placed in a hypotonic solution the cell will implode (not explode, thus the water will push the cell on itself until implosion occurs.) Last but not least a hypertonic solution will cause the cell to explode by too much water entering the cell because there is already more water in the cell then in the solution. So the simple answer is: Isotonic solution= nothing, hypotonic solution= implosion, and hypertonic solution= explosion.
Isotonic solution is a solution which contains the same concentration as present in cell. So no osmosis will occur. Hence there will be a neutral effect.
well it would be that their is an equal amount of solution inside and outside the cell. it is neither hypotonic or hypertonic. it is balanced or equal.