answersLogoWhite

0


Best Answer

If magnesium loses two electrons and form Mg2+ ion, it will get the configuration of the nearest noble gas, neon

User Avatar

Wiki User

11y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

6mo ago

Magnesium has an atomic number of 12, which means it has 12 electrons. To achieve a noble gas configuration, magnesium would need to lose both of its valence electrons. This can be achieved through chemical reactions, where magnesium can form ionic compounds by transferring its electrons to other elements, such as oxygen or chlorine.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What would make it possible for a magnesium to have a noble gas configuration?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the noble gas notation for Xenon?

Xenon is a noble gas, so its noble gas configuration would be [Xe] Its configuration using the short-cut method would be [Kr]5s24d105p6


Which noble gas would be listed in the noble-gas configuration of copper Cu?

Argon


What is the valence electron configuration for the magnesium atom?

Magnesium (Mg) has atomic number 12, so the electron configuration is1s2 2s2 2p6 3s2. The VALENCE electron configuration would simply be 3s2.


How many electrons would calcium have to give up to achieve a noble-gas configuration?

Calcium has to lose 2 electrons to form noble gas configuration.


What is the noble gas configuration of nitrogen?

The noble gas configuration for nitrogen is [He] 2s2 2p3per the notation protocol.


How would you draw the electron configuration for Magnesium?

1s2 2s2 2p6 3s2


What is the noble gas notation of beryllium?

There are two possible 'noble gas' configurations:2 8 18 32 18 8 for Bi3-, or in shorthand configuration [Xe] 4f14, 5d10, 6s2 6p6and2 8 18 32 18 0 for Bi5+, or in shorthand configuration [Xe] 4f14, 5d10, 6s0 6p0Bismuth (as metaloid atom) in elemental notation: [Xe] 4f14, 5d10, 6s2 6p3


What is Noble gas configuration of silver?

the noble gas configuration of silver would be [Kr]4d105s1, because the s orbital is the valence shell, whereas the d orbital is a lower energy level. Thus, it would not be [Kr]4d95s2.


How would you explain the fact that the first ionization enthalpy of sodium is lower than that of magnesium but its second ionization enthalpy is higher than that of magnesium?

Sodium has only one valence electron, and when that is donated to some other atom, the remaining ion has a noble gas configuration that is highly stable. Disrupting that by another ionization requires much energy. Magnesium has two valence electrons; therefore the second is almost as easy to donate as the first. The third ionization enthalpy of magnesium would be very high.


Why does the magnesium atom tend to form the 2 ion?

Magnesium has two outer shell electrons which are loosely held. This is not a stable configuration. As a result magnesium will lose those two electrons, making the electron shell below that, which has 8 electrons, the new outer shell. An electron shel with 8 electrons is stable.


How many electrons must be lost given the following atoms Ca Mg Ba Be to attain Noble gas?

To attain the noble gas configuration, Ca would have to lose 2 electrons, Mg would have to lose 2 electrons, Ba would have to lose 2 electrons, and Be would have to lose 2 electrons.


How many electrons does BR need to achieve noble gas?

To achieve noble gas configuration, Bromine must gain one electron. In doing so, it obtains the electron configuration of Krypton. It's new complete electron configuration would be: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.