You could increase its volume or cool it or both.
Increase it by 4 times.
An ideal gas will have a volume that is inversely proportional to the pressure (assuming constant temperature). For example, if you double the pressure, the volume will be reduced to 1/2 the original volume. For real gases, the behavior is usually somewhat different. In some cases, if you double the pressure, the volume will reduce to LESS than 1/2 the original volume. This is due to the attraction between the molecules, and this phenomenon is called "supercompressibility".
according to the ideal gas equation , volume will be four time of initial value.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
Pressure in a glass can be reduced by either decreasing the amount of the gas in a finite space, or by increasing the volume of the finite space.
decreasing the volume available for the gas or increasing its temperature
It would be half of the original volume. As you reduce the volume the pressure would increase and at half the original volume the pressure would be doubled.
An ideal gas will have a volume that is inversely proportional to the pressure (assuming constant temperature). For example, if you double the pressure, the volume will be reduced to 1/2 the original volume. For real gases, the behavior is usually somewhat different. In some cases, if you double the pressure, the volume will reduce to LESS than 1/2 the original volume. This is due to the attraction between the molecules, and this phenomenon is called "supercompressibility".
Assuming it's a bag of gas at constant temperature, four times the volume by the relationship: P1V1 = P2V2
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
according to the ideal gas equation , volume will be four time of initial value.
BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature Answer BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
To increase the volume of a gas * reduce the pressure, or * increase the temperature, or * add more gas
The volume, in this case, will reduce by a factor of 4 (i.e., to 1/4 of its previous volume).
20psi
Pressure in a glass can be reduced by either decreasing the amount of the gas in a finite space, or by increasing the volume of the finite space.