Does not matter. But in a practical sense Its cheaper to get heat from high voltage because smaller wire, smaller breakers, and definitely less heat loss from the circuit wiring. It's called ixiR loss. Same reason overhead transmission lines are obcenely high voltage values.
It is all relative. Heat equals this times that. Lower this, raise that. Horsepower equals this times that. Lower rpm, raise torque or vice versa.
Navy wants planes to fly faster, lose weight, raise hydraulic pressure, reduce hydraulic line size. Electric, hydraulic, mechanical, it's all equal.
At 240 v and 50 amps the power is 12 kW because 240x50 is 12,000.
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
The formula you are looking for is W = A x V. Then divide the wattage figure by 1000 to change watts to kilowatts.
That is 50,000 BTU per hour.
decreasing the voltage and increasing the ohms
The output of an electric fencer is a high voltage pulse of DC voltage.
At 240 v and 50 amps the power is 12 kW because 240x50 is 12,000.
Yes, voltage effects the output of electric heaters. The wattage output rating of the heater will not be reached due to the lower applied voltage. For example if the heater is 5000 watts at 277 volts, the current is I = W/E 5000/277 = 18 amps. The resistance of the heater is R = W/I (squared) = 5000/18 x 18 (324) = 15.43 ohms. Applying 220 volts on the same heater whose resistance is 15.43 ohms results in this new heater wattage rating. W = E (squared)/R = 220 x 220 (48400)/15.43 = 3137 watts. W = watts, I = amperage, R = resistance in ohms and E = voltage.
At 240 v and 50 amps the power is 12 kW because 240x50 is 12,000.
2kw = 6,827 Btu/ Hr 5kw = 17,076 Btu/Hr 5kw yields 10,249 Btu more /Hr
Because the windings of transformers have resistance, the primary and secondary currents will cause voltage drops. To compensate for the drops, the transformer may have been designed to have a higher than specified output voltage when there is little or no output current. The no load output voltage typically is only slightly greater than the specified voltage. Before measuring the output voltage, measure the input (line) voltage. If it is not as specified for the transformer, calculate its effect on the output.
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
36V to 72V
The AVR (Automatic Voltage Regulator) control the DC field voltage to the rotor of the alternator, as soon as higher load is demanded from the alternator, the AVR output voltage go higher, hence, a higher AC voltage on the output of the alternator. If the voltage go to high then the AVR is faulty.
The formula you are looking for is W = A x V. Then divide the wattage figure by 1000 to change watts to kilowatts.
Output power can never be more than input power. With a transformer, it is possible to increase the output current (while decreasing the output voltage), or to decrease the output current (while increasing the output voltage).
That is an electric AC or audio output, where the voltage is measured in volts rms. Scroll down to related links and look for "dB conversion (decibel)". Look there in the middle at this headline: "RMS voltage, peak voltage and peak-to-peak voltage".