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Silver sulfide Ag2S -Molar mass: 247.9 g/mol .

Thus 2 moles of silver will react with one mole of sulphur.

Silver Atomic Mass: 107.9 so 4 g = 0.0370713623725672 of a mole

Sulphur Atomic mass 32.1 so 4 g= 0.1246105919003115 of a mole

Ag2S -Molar mass: 247.9 g/mol - which is 32.1 g of Sulphur + 2 times 107.9 = 215.8 g of Silver

Therefore 32.1/215.8 = 0.1487488415199259 the ratio of the masses

Therefor Silver 4 g * 0.1487488415199259 = 0.5949953660797034 g of Sulphur

Therefore the mass of Silver sulphide produced is 4.5949953660797034 grams,

With 4-0.5949953660797034 = 3.405004633920297 g of sulphur left over.

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Q: When 4.00 g of silver reacts with 4.00 g of sulphur what mass of silver sulfide is produced?
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