(This question is answered below by assuming that the lower-case "m" in the first line of the question was intended to be a capital "M" as in the second line. If the "m" was intended to mean "molality" rather than molarity, the question can not be answered without additional information, specifically the density of the Pb(NO3) solution at the temperature at which the volume specified was measured.)
The formula for a "mole" [more strictly, "formula unit"] of the lead nitrate solution given in the question shows that each unit contains one lead cation. The KI solution is stated to be in excess, so that every lead cation supplied to the reaction will be precipitated.
A 2.0 molar solution by definition contains 2.0 moles of lead cations in each liter of solution. The solution is homogeneous. therefore, 500ml of it will contain half as many lead cations, in this instance 1.0. Therefore, 1.0 moles of lead (II) iodide will be precipitated.
approx 2.4354g
A precipitate of yellow Lead iodide and Sodium nitrate are formed
It is left as a low hazard
Iodide is an ion formed from the element iodine, so it is not a compound.
Having assets in excess of liabilities; able to pay one's debts.
approx 2.4354g
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
A precipitate of yellow Lead iodide and Sodium nitrate are formed
It is left as a low hazard
When aqueous solutions of silver nitrate and sodium iodide [note correct spelling] are mixed, silver iodide solid precipitates from the mixture.
Silver nitrate for example: AgI(s) silver iodide
Iodide is an ion formed from the element iodine, so it is not a compound.
Yes it can be and the solution formed is called aerosol. e.g.Sponge
DIluted milk? -_-
A solution of calcium chloride is formed.
Having assets in excess of liabilities; able to pay one's debts.
Any reaction; iodine is used to test the contamination with starch.