C6H12O6 + 6O2 ==> 6CO2 + 6H2O (balanced equation)
9.00 g x 1 mole/180 g = 0.05 moles C6H12O6
0.05 moles C6H12O6 x 6 moles CO2/1 mole C6H12O6 x 44 g CO2/mole CO2 = 13.2 g CO2 formed
When 9.00 g c6h12o6 burns with excess oxygen 13.2 grams of CO2 will be made.
13,19 g carbon dioxide are obtained.
14,64 g carbon dioxide are obtained.
6.08
51.4 - 51.8
The percentage of oxygen is 54,84 %.
320 grams of oxygen is the equivalent of 10 moles.
16 grams of oxygen how many moles is 0,5 moles.
This question needs additional information to enable me correctly answer it.
6.08
28g Fe
This question is not specific and can therefore not be answered accurately.
51.4 - 51.8
62.1 - 62.5
0.44g. Molecular weight is 24.3. 0.44/24.3 is 0.0181 moles
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The percentage of oxygen is 54,84 %.
The answer is 224,141 grams oxygen.
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
320 grams of oxygen is the equivalent of 10 moles.