Use the equation I=q/t, where I is amperes, q is coulombs and t is time in seconds.
First you have to convert the minutes to seconds, so 60 x 8= 480 seconds. Then
I=1100/480. I = 2.29 amperes.
528000
375 kj
A Miniature Circuit Breaker or "MCB" works as a normal electrical circuit breaker but is a much smaller device. As well as electro-mechanical relay technology it includes electronic circuitry to achieve its small overall size. MCBs are now used extensively for consumer power-distribution panels and inside small electrical equipment.For more information see the answers to the Related Questions and also the Related link shown below.
In the US, it only takes a couple of minutes for a power company electrician to install an electric meter on a new service. The drop from the power line is made to an electrical connection box in the house, and the box has the meter base built into it. The meter basically "bayonets" into the base, and then is secured. Some kind of a "tamper indicator" is then affixed so that the meter cannot be removed without breaking that indicator. With the panel in place and properly wired and inspected, the power company electrician can have the meter in and buttoned up in just a couple of minutes.
Creep in electricity is the full revolution of the metal disk in a meter. The creep allows for one full revolution every ten minutes.
Quarter past is an expression 15 minutes past the current hour. Each quarter of an hour is 15 minutes. So quarter past 10 is equal to 10:15.
Assuming that you're truly running the bulb with 12 volts . . .(2 amperes) x (12 volts) = 24 watts = 24 joules per second(24 joules/second) x (60 seconds/minute) x (20 minutes) = 28,800 joulesAlso, in electric-bill terms ... 0.008 kilowatt-hour
1.22x10^4c
A current of 32 amperes for 2 minutes represents a current flow of 3,840 coulombs.One ampere is one coulomb per second.
1 Ampere = 1 Coulomb per second0.25 A = 0.25 Coulomb per sec1 minute = 60 seconds20 minutes = (20 x 60) = 1,200 seconds0.25 A for 20 minutes = (0.25 x 1,200) = 300 Amp-seconds = 300 Coulombs of charge
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
Not enough information. To get the amount of electrical energy, you need to multiply the power used (in Watts) by the time (in seconds). The power used is not equal to the voltage; it is volts x amperes. Look for a metal sticker that shows the electrical characteristics of the device; it should show the amount of Watts used. If it only shows Volts and Amperes, multiply both to get the amount of Watts. (Technically there is also a power factor, but that can often be ignored.)
233 is just a dimensionless number. There are no hours, minutes,light-years, amperes, kilograms, or anything else in it.
At least 60 minutes because they contain capacitors which hold electric current.
375 kj
60 minutes
120 V x 0.75 A = 90 watts2 minutes = 120 seconds90 watts for 2 minutes = (90) x (120) = 10,800 watt-seconds = 10,800 joulesThe motor consumes 10,800 joules of electrical energy during that 2 minutes.If the motor is perfectly (100%) efficient, then that's the amount of work youcan get out of it.In the general case, the amouunt of work the motor can do is (10,800 joules) x the motor's efficiency.
15 minutes.