1.22x10^4c
The short answer is it depends, the long answer is more complicated.... First thing to say is that it is not the volts that are fatal in an electric shock, it is the amps. To make an analogy between electricity and water being pumped through a pipe the voltage is the strength of the pump and the amps are the volume of water (or slightly less accurately the thickness of the pipe). Hence the voltage is how much the electricity is being 'pushed' and the amps are the actual 'amount' of electricity. It is for this reason that while tazer guns deliver a shock with a power of 10,000 volts they are generally not fatal because they deliver very few amps, while home circuits have much lower voltages (110v US, 230v/240v in Europe/UK) they are capable of delivering much higher ampages and can therefore be fatal and extremely damaging to the human body. They are also capable of pushing electricity through many other substances, such as air meaning direct contact with them isn't always needed. This said technically a shock of .1 amps can be fatal is applied directly to the heart as it will cause it to stop beating, it can also have the opposite effect and cause it to start beating again (hence defribulation). To put that in context in the UK home socket circuits are rated at 32 to 45 amps and cooker circuits are generally rated at 45amps. The other major risk of high amps however is that when electricity passes through a substance it creates heat. The higher the amps the higher the potential heat the current will generate and the longer you are part of the circuit the closer to that potential heat you will become. So the dangers of an electric shock on the typical amps found in a home are instant cardiac arrest or deep full thickness burns and internal organ damage as the electrical current literally cooks you from the inside. As for shocks from powerlines, well they have massive voltages (meaning they can push the electricity along way through the air) and massive amperage meaning they will burn you (cook you more actually) very very quickly leading to massive tissue damage meaning even if your heart isn't stopped or you are revived after the shock you will still probably die from the burns and organ failure.
The process of decomposition of an electrolyte, by passing an electric current from an outside source through it, is known as electrolysis. For example, when an electric current is passed through acidified water, water is decomposed into hydrogen and oxygen.
about one minute
choanocytes are resonsible for current flow and trapping food particles in sponges source: my invertebrate zoology textbook :)
Due to the induced voltage in the cable gland by the current flowing through the conductors enclosed by the armour.
Current in amperes is coulombs per second, so 2 coulombs per second is 2 amperes.
Divide the coulombs by the amperes. The answer will be in seconds. The resistance is irrelevant in this problem.
Use the equation I=q/t, where I is amperes, q is coulombs and t is time in seconds.First you have to convert the minutes to seconds, so 60 x 8= 480 seconds. ThenI=1100/480. I = 2.29 amperes.
For a steady flow of charge through a surface, the current I in amperes can be calculated with the following equation:I = Q/t where Q is the electric charge transferred through the surface over some time t. If Q and t are measured in coulombs and seconds respectively, I is in amperes. Thus: I = 0.24 coulombs / 15 msec I = 0.24 coulombs / 15 * 10^-3 sec I = 16 amps
A flow of 7400 coulombs in 85 seconds represents a current of 87 amperes. One ampere is one coulomb per second, so divide 7400 by 85.
elelctric current
Current flow is when charge moves from one point to another. It is measured in coulombs per second, which is more commonly known as amperes.
Here we are given 3.1 amperes of current and are asked to find the time it takes 10 coulombs of charge to pass a given point. First ask yourself how many coulombs are passing a given point in one second. If we have 3.1 amperes of current, we have 3.1 coulombs of charge passing any given point in one second. If it takes 1 second for 3.1 coulombs of charge to pass, how long will it take for 10C of charge to pass?
Current = charge / time Charge q = n * e e = 1.602 x 10^-19 C time given = 0.2 s Current = 0.5 A So I = n e / t Hence n = I * t / e Plug I, t and e. You would get required n ANS: 6.24 x 10^17 electrons
250 mA = 0.25 Ampere = 0.25 coulomb per second.(0.25 coulomb/second) x (60 sec/minute) x (30 minutes) = 450 coulombs
if you want to find the current (in amperes) through the resistor then connect a ammeter in series with the resistor.
'E' = voltage across the lamp = 230'I' = current through the lampPower = 60 watts = E x I = 230 II = (60 / 230) Amperes = (60/230) Coulombs per second.1/2 hour = 1,800 seconds.Total charge in 1/2 hour = (60/230) x (1,800) = 469.57 coulombs (rounded)