250 mA = 0.25 Ampere = 0.25 coulomb per second.
(0.25 coulomb/second) x (60 sec/minute) x (30 minutes) = 450 coulombs
low is below 600V medium 600 to 2500V High above 2500V usually medium and high voltage equipment is called switchgear the current is monitored and 3 shorts within 10 minutes will open the switch overloads are usually 200% for over 20 minutes but the big stuff is programable
Will damage
The current in a circuit is a measure of passing electrical charge per second. Each electron carries a fix amount of charge. Therefore the number of charge moving depends on the speed of the charge, in this case electrons. In conductors like copper, there are just so many free electrons that they move in bulk slower than snail. The the Cathode ray tube, the speed is at a fraction of speed of light, not many electrons are flying. For actual number, look up speed of electron in copper at room temperature, and multiple the electrical charge constant to get at the current. This must be a standard class tutorial.
5 A Q / t = I so 1200/4*60 = 5 A
120 V x 0.75 A = 90 watts2 minutes = 120 seconds90 watts for 2 minutes = (90) x (120) = 10,800 watt-seconds = 10,800 joulesThe motor consumes 10,800 joules of electrical energy during that 2 minutes.If the motor is perfectly (100%) efficient, then that's the amount of work youcan get out of it.In the general case, the amouunt of work the motor can do is (10,800 joules) x the motor's efficiency.
The charge transferred in 25 minutes by a current of 500 mA is 750 coulombs. Amperes is defined as coulombs per second, so 500 mA is 0.5 coulombs per second. 25 minutes is 1500 seconds, so the charge is 750 coulombs.
1 Ampere = 1 Coulomb per second0.25 A = 0.25 Coulomb per sec1 minute = 60 seconds20 minutes = (20 x 60) = 1,200 seconds0.25 A for 20 minutes = (0.25 x 1,200) = 300 Amp-seconds = 300 Coulombs of charge
1.22x10^4c
Use the equation I=q/t, where I is amperes, q is coulombs and t is time in seconds.First you have to convert the minutes to seconds, so 60 x 8= 480 seconds. ThenI=1100/480. I = 2.29 amperes.
1 A = 1 coulomb per second(0.25 coulomb/sec) x (10 minutes) x (60 sec/min) = 150 coulombs
A Miniature Circuit Breaker or "MCB" works as a normal electrical circuit breaker but is a much smaller device. As well as electro-mechanical relay technology it includes electronic circuitry to achieve its small overall size. MCBs are now used extensively for consumer power-distribution panels and inside small electrical equipment.For more information see the answers to the Related Questions and also the Related link shown below.
At least 60 minutes because they contain capacitors which hold electric current.
375 kj
That completely depends on how much current is used by the circuit or device that's connected to the battery. For example, if there is no circuit or device connected to the battery, and no current is used, then the battery lasts for quite a long time. But if you lay a screwdriver across the battery terminals and create great balls of fire, then the charge on the battery may only last for 1/2 second.
15 minutes.
It depends. Do you have a gas or electric stove. If you have electric about 2-3 minutes. If you have a gas stove about 4 minutes. Hope this answers your question
12 minutes