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This is a limiting reagent stoichiometry problem, so that means you have to run the calculations twice; once for 5 grams of silver and once for 5 grams of sulfur. When you do this, you'll find that for 5 grams of silver (and an excess of sulfur) you would get 5.68 g of product, and for 5 grams of sulfur (and an excess of silver) you would get 39.52 g of product. So, you have to go with the less of the two amounts, because that's the most you can ever produce. So the answer is 5.68 g of silver(I) sulfide, with silver being the limiting reagent.

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Q: When a mixture of silver metal and sulfur is heated silver 1 sulfide is formed What mass of silver 1 sulfide is produced from a mixture of 5.0 g of Ag and 5.0 g of S?
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