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When a photon is emmit out from the atom its color is same as the atom color?
Wiki User
∙ 13y ago
No. The color of the electron depends on the energy difference between the levels from/to which it is changing.
Wiki User
∙ 13y ago
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What determines which photon an atom can absorb or emit?
Generally if they are of the same wavelength, then the atom will absorb the photon at that wavelength.
If a certain fluorescing dye was2 emit a photon with an energy of 4.1x10-19J would this a suitable candidate for a light stick would this photon then be the same as the photon of a hydrogen atom?
no
What must happen for an atom to go from an excited state to a ground state so color is seen?
An excited electron spontaneously drops back to its ground state, emitting a photon of light as it does so. <><><><><> The same thing happens in the nucleus. An excited nucleus drops down to a lower energy level, releasing a photon.
Are protons and photons the same thing?
No. A proton is a part of an atom, while a photon is a tiny bundle of light energy (or light particle).
How does the energy of three photons of blue light compare with that of one photon of blue light from the same source?
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
When an electron drops to a lower energy level what is the energy of the photon released?
The energy of the photon is the same as the energy lost by the electron
What is the difference between emission and absorption?
Emission is something be spread out, while absorption is something being taken in.
How does the material used in a laser affect the type of light emitted?
To make an atom emit light, an atom in the outer shell, or valence shell, must be knocked into a higher orbit. When it falls back to its valence shell, it falls back a specific distance and emits a photon of a specific wavelength. We see that as light of a particular color. Every element will have the orbit above the valence shell at exactly the same place. Each material will emit light of exactly the same color. To get a laser that will emit different colors, you would need to make your laser from several different materials.
How does the materials used in a laser affect the type of light emitted?
To make an atom emit light, an atom in the outer shell, or valence shell, must be knocked into a higher orbit. When it falls back to its valence shell, it falls back a specific distance and emits a photon of a specific wavelength. We see that as light of a particular color. Every element will have the orbit above the valence shell at exactly the same place. Each material will emit light of exactly the same color. To get a laser that will emit different colors, you would need to make your laser from several different materials.
How can an atom of size 1angstrom can absorb a photon of 5000 wavelength?
I presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?" The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength. A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy. You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
What happens when an atom absorbs energy?
It is actually the nucleus of the atom that emits energy. The energy we can harness comes from fission or splitting of the nucleus of uranium235 or plutonium239. The nucleus splits into two parts which recoil and give up their kinetic energy as heat when they are stopped in the fuel, and there is also some energy from gamma rays at the same time. Basically in the process the final results of the fission have lost mass, and this appears as energy following the relation E = M x C2. Atoms can also emit energy as radioactivity, without fissioning. This can be alpha, beta, or gamma radiation. Alpha and beta are particles, so that the resulting nucleus is changed and there results a different element. Gamma is a penetrating ray in the electromagnetic spectrum and corresponds to a change in the energy state of the nucleus, but it remains the same element.
When an electron drops to a lower energy level what is the energy of a photon released?
The energy of the photon is the same as the energy lost by the electron
