The energy of the photon is the same as the energy lost by the electron
The energy of the photon is the same as the energy lost by the electron
When an electron drops from a higher energy state to a lower energy state, it emits electromagnetic radiation in the form of a photon. This process is known as atomic emission, and the energy of the emitted photon corresponds to the energy difference between the two electron states.
When an electron drops from level 5 to level 1, a photon is emitted in the ultraviolet region of the electromagnetic spectrum. The energy released corresponds to the energy difference between the two electron levels, which is characteristic of ultraviolet light.
No, when an electron drops from a higher energy level to a lower energy level within an atom, the energy released in the form of a photon is given off by the electron itself, not taken from the environment. This process is known as emission.
You may be confusing "proton" with "photon". A proton is a positively-charged particle contained within the nucleus of an atom. A photon is a discrete unit of energy normally expressed as light. Around the nucleus of the atom, there are some electrons in energy levels. When an atom absorbs energy, it absorbs a specific amount, or "quantum" of energy and the electron boosted to a higher energy level. When the electron drops to a lower energy level, it emits a photon in the form of light at a specific energy and frequency.
Drops to a lower energy level and emits one photon of light.
When light (a photon) collides with an atom, the energy contained by it is absorbed and it bumps one of the electrons orbiting it up to a higher energy level. ( there are several energy levels, think of it as stories of a building) Later when the electron falls down 1 or more energy levels, The energy is released as another photon. If the electron drops down to the original energy level, the same intensity photon is released as was absorbed. If it drops down in 2 or more steps, several photons will be released of varying intensity, depending on the amount of levels dropped.
When an electron drops from the 7th to the 2nd energy level in an atom, it emits a photon of light. The energy of this photon corresponds to the difference in energy between these two levels. The amount of energy difference is specific to the atom involved, and the photon emitted will have a specific wavelength and color based on this energy difference.
It gains energy in a quantized amount
Lots of wrong answers out there, tested this on school, the answer is: Drops from a higher to a lower energy level
In a transition to ground state, a photon is radiated away. It carries off the energy to make a transition to ground state possible. As soon as it is created, the photon is off to the races. It travels away at the speed of light (for the medium in which it is moving).
All transitions in which electrons move from a lower to a higher level require a gain of energy. example: 2nd to 3rd shell