The energy of the photon is the same as the energy lost by the electron
You may be confusing "proton" with "photon". A proton is a positively-charged particle contained within the nucleus of an atom. A photon is a discrete unit of energy normally expressed as light.
Around the nucleus of the atom, there are some electrons in energy levels. When an atom absorbs energy, it absorbs a specific amount, or "quantum" of energy and the electron boosted to a higher energy level. When the electron drops to a lower energy level, it emits a photon in the form of light at a specific energy and frequency.
A proton is not released.
The energy of the photon released will depend on the initial energy level and the subsequent energy level.
The energy of photon is the difference between the first and second state of the electron.
What is the first quantum number of a 2s2 electron in phosphorus,
1s22s22p63323p3?
Ultraviolet
No, the energy released by electron might be taken by enviornment. Electron remains in the infuence of corresponding nuclei, in another energy level.
An electron has dropped from a higher energy state to a lower one. The photon emitted has precisely the same energy as was lost by the electron.
All transitions in which electrons move from a lower to a higher level require a gain of energy. example: 2nd to 3rd shell
Lots of wrong answers out there, tested this on school, the answer is: Drops from a higher to a lower energy level
The energy of the photon is the same as the energy lost by the electron
A photon is emitted when an electron falls from a higher to lower orbital. A photon is an elementary particles, the quantum of light and all other forms of electromagnetic radiation.
When light (a photon) collides with an atom, the energy contained by it is absorbed and it bumps one of the electrons orbiting it up to a higher energy level. ( there are several energy levels, think of it as stories of a building) Later when the electron falls down 1 or more energy levels, The energy is released as another photon. If the electron drops down to the original energy level, the same intensity photon is released as was absorbed. If it drops down in 2 or more steps, several photons will be released of varying intensity, depending on the amount of levels dropped.
You may be confusing "proton" with "photon". A proton is a positively-charged particle contained within the nucleus of an atom. A photon is a discrete unit of energy normally expressed as light. Around the nucleus of the atom, there are some electrons in energy levels. When an atom absorbs energy, it absorbs a specific amount, or "quantum" of energy and the electron boosted to a higher energy level. When the electron drops to a lower energy level, it emits a photon in the form of light at a specific energy and frequency.
Drops to a lower energy level and emits one photon of light.
Only one photon is produced per electron in any de-excitation. The number of energy levels it drops only determines the energy of the photon emitted.
Ultraviolet
No, the energy released by electron might be taken by enviornment. Electron remains in the infuence of corresponding nuclei, in another energy level.
An excited electron spontaneously drops back to its ground state, emitting a photon of light as it does so. <><><><><> The same thing happens in the nucleus. An excited nucleus drops down to a lower energy level, releasing a photon.
An electron has dropped from a higher energy state to a lower one. The photon emitted has precisely the same energy as was lost by the electron.
It gains energy in a quantized amount
All transitions in which electrons move from a lower to a higher level require a gain of energy. example: 2nd to 3rd shell