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ONLY in pure water at 25 0C :pH + pOH = 14.00
6 x 5 25 + 5 35 - 5 150 ÷ 5
pH = -log(concentration of H+ ion) which indicates acid pOH = -log(concentration of OH- ion) which indicates base In pure water at 25 degree Celsius, concentration of H+ and OH- is equal i.e. 10^-7 mol/dm^3 so, the sum of pH and pOH is -log(10^-7) + -log(10^-7) = 7 + 7 = 14
1 x 250, 2 x 125, 5 x 50, 10 x 25 and 125 + 125 = 250
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
The sum of the first 25 prime numbers is 1,060.
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
The sum is 14913.
The sum of the first 25 prime numbers is 1,060.
The total sum is: 25+52+10 = 87
na+oh +25=53 ph+poh=2.3
Sum of 1,2, ... , n is n*(n+1)/2 Here, n = 25 so sum = 25*26/2 = 325