You can use either. I assume the 240 volts is the line to neutral voltage, and the 415 is the line to line voltages. They will both give you the correct answer. It is important to note these values are RMS, not 0 - peak voltages, but this may be beyond your question. The equations below are for calculated from RMS values (both voltage and current).
If you are using a L-L voltage, P = I*V*sqrt(3)
If you are using the L-N voltage, 1-phase power P = I*V (for the power in a single phase, for all three, multiply by 3), or 3phase power P = 3*I*V
You will get the same answer, since the L-N voltage is (1/sqr(3)) times the L-L voltage.
according to energy heat equation e=mc^2 where c is speed we can calculate energy
The equation you need to find amperage when kilowatts are known. Amps = kW x 1000/1.73 x volts x PF. Use .9 as a Power Factor constant.First megawatts must be changed to kilowatts. 1000000/1000 = 1000 kilowatts. Amps = 1000 x 1000/ 1.73 x 480 x .9 = 1000000/747 = 1338.6 amps.
KVA (kilovoltamperes) is KW (kilowatts) divided by sin(90 - theta) where theta is the phase angle between voltage and current. This answer assumes a sinusoidal, linear load.
virtual circuit
A circuit in which loads are connected side by side is known as a parallel circuit.
velocity=acceleration multiplied by time
according to energy heat equation e=mc^2 where c is speed we can calculate energy
the ABACUS. it is also known as the 1st calculating device created by the Chinese. it is also known as the 1st computer.
The equation you need to find amperage when kilowatts are known. Amps = kW x 1000/1.73 x volts x PF. Use .9 as a Power Factor constant.First megawatts must be changed to kilowatts. 1000000/1000 = 1000 kilowatts. Amps = 1000 x 1000/ 1.73 x 480 x .9 = 1000000/747 = 1338.6 amps.
If a dynamo puts out 100,000 kilowatts and the area it services only requires 80,000 kilowatts; then the remaining 20,000 kilowatts is known as its residual power. This extra capacity is useful in withstanding power spikes when consumer demand increases during peak periods.
KVA (kilovoltamperes) is KW (kilowatts) divided by sin(90 - theta) where theta is the phase angle between voltage and current. This answer assumes a sinusoidal, linear load.
This is what is known as a "short circuit".
Calculating clock is the first known calculating device made by Wilhelm Schickard. This machine can perform the basic mathematical operation, but canÕt show too large result which is limited to six digits.
A closed path through which electrons flow is known as a circuit.
virtual circuit
virtual circuit
A circuit in which loads are connected side by side is known as a parallel circuit.